(1/9)^x-28(3^-x)+27=0

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Solution for (1/9)^x-28(3^-x)+27=0 equation: 



(1/9)^x-28(3^-x)+27=0



Domain of the equation: 9)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/9)^x-28(3^-x)+27=0

We multiply parentheses

(+1/9)^x+28x+27-=0

We multiply all the terms by the denominator


(+1+28x*9)^x+27*9)^x-()*9)^x=0

We add all the numbers together, and all the variables

(28x*9+1)^x+27*9)^x-()*9)^x=0

Wy multiply elements

2187x^2+(28x*9+1)^x=0

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